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14.3 g  Na2CO3.XH2O                                          ()
                                              at STP CO2
                          .                                            1.12 L

[ Na = 23 , C = 12 , O = 16 , H = 1 ]

                                                                                    ‫ﺍﻟﺤــﻞ‬

Na2CO3 + 2HCl                          2NaCl + H2O + CO2

1 mol                                                        1 mol

( 2 X 23 ) + 12 + ( 3 X 16 )                    1 X 22.4

106 g                                           22.4 L

X g 1.12 L

        X = 106 X 1.12 = 5.3 g

                          22.4

                                                                    5.3 g = Na2CO3  
                                                                                    
       9 g = 5.3 – 14.3 =                        –

Na2CO3 ‫ ﻣ‬5.3 g                         H2O 9 g

Na2CO3 ‫ ﻣ‬106 g                         H2O X g

 X = 9 X 106                 = 180 g

               5.3

                                       18 g/mol = 16 + ( 2 X 1 ) = H2O

                                       10 mol =     180             =

                                                    18

١١١  

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