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14.3 g Na2CO3.XH2O ()
at STP CO2
. 1.12 L
[ Na = 23 , C = 12 , O = 16 , H = 1 ]
ﺍﻟﺤــﻞ
Na2CO3 + 2HCl 2NaCl + H2O + CO2
1 mol 1 mol
( 2 X 23 ) + 12 + ( 3 X 16 ) 1 X 22.4
106 g 22.4 L
X g 1.12 L
X = 106 X 1.12 = 5.3 g
22.4
5.3 g = Na2CO3
9 g = 5.3 – 14.3 = –
Na2CO3 ﻣ5.3 g H2O 9 g
Na2CO3 ﻣ106 g H2O X g
X = 9 X 106 = 180 g
5.3
18 g/mol = 16 + ( 2 X 1 ) = H2O
10 mol = 180 =
18
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