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-                                                     ()
                                                                                   ‫ﺍﻟﺤــﻞ‬
          0.2 mol                                                       1L
                                                                                    
           H2(g)         +       I2(g)                    2HI(g)
          1 mol                1 mol                     0 mol
                                                   0 + (2 X 0.8) mol
1 – 0.8 mol 1 – 0.8 mol

             0.2 mol 0.2 mol                       1.6 mol

                                                                           1L

Kc =         [ HI ]2        =        [ 1.6 ]2      = 64
                                  [ 0.2 ] [ 0.2 ]
          [ I2 ] [ H2 ]

      N2 (g) + 3H2 (g)            2NH3(g)                                           ()
500 K 20 L
                                                   5 mol                    5 mol  ‫و‬
        . Kc
                                                          0.25 mol

                                                                                   ‫ﺍﻟﺤــﻞ‬

           N2(g) +             3H2(g)              2NH3(g)
          5 mol                5 mol               0 mol

5 – 0.25 mol 5 – (3 X 0.25) mol 0 + (2 X 0.25) mol

          4.75 mol             4.25 mol            0.5 mol

[ N2 ] =     4.75       =   0.2375 M       [ H2 ] =       4.25 = 0.2125 M
             20                                            20

[ NH3 ]      0.5
=            20 = 0.025 M

      KC  =     [NH3]2            =           [0.025]2                  0.274
             [ N2] [ H2 ]3
                                                                     =

                                        [ 0.2375] [ 0.2125]3

١٣٥  

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