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36.5 g/mol = 35.5 + 1 = HCl

              0.02 mol =  0.73              g           = HCl
                          36.5
                                   = (g/mol)

                0.4 mol / L =             0.02     =          = HCl
              NaOH + HCl                  0.05

                                          5
                                                  NaCl + H2O

                                   Ma Va    = Mb Vb

                                     na

                          0.4 X 150 = 0.5 X Vb                   120 ml = Vb
                               11

(0.4 M)                            1 L (0.3 M)                   1 L (٦)

                                                          .

Ba(OH)2 = 171 g/mol , BaSO4 = 233 g/mol , H2SO4 = 98 g/mol

              0.4 mol = 1 X 0.4 =               X                    ‫ﺍﻟﺤــﻞ‬

              0.3 mol = 1 X 0.3 =           X                        
                                                                       
                         CaCl2 + H2SO4  2HCl + CaSO4                  
                                            1:1
                                                                            
              0.3 mol =

                          0.1 mol = 0.3 – 0.4 =

              Ba(OH)2 + H2SO4  BaSO4 + 2H2O

                                   1 mol         1 mol

                                   1 mol  233 g

                                   0.1 mol  X g

                                23.3 g = (            )X

١١٦

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