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ELECTRICAL ENGINEERING UNIVERSITAS KRISTEN INDONESIA PAULUS , MAKASSAR
Soal 4. ( + ) + = ( + )
Penyelesaian :
( + ) ( + )
+ =
+ + +
+ = +
+
+ =
+ = + ; maka P = ; Q = +
+ +
∫ P dx = ∫ . dx
+
∫ P dx = ln( + 1)
FI = e ∫ P dx = e ln( +1) = ( + 1) → faktor integrasi
= ∫ . .
y ( + 1) = ∫ x + 1. ( + 1). dx
2
y ( + 1) = ∫( + 1) . dx
1 3
y ( + 1) = ( + 1) +
3
1 ( +1) +
3
y = 3
( +1)
1 3
y = 3 ( +1) +
( +1) ( +1)
−
= ( + ) + ( + )
Hestikah E Patoding (hestikah@ukipaulus.ac.id) | Calcullus III - Persamaan Diferensial Orde Pertama I - 7
