105
1
= −2
+1 2
−1
= ;2
[ +1− −1 ] 2
−1
= ;2
( ;1) 2
;1 ′ = ;2
( ;1) 2
CONTOH:
2
Tentukan ;1 ′ 3 , jika = − 2 + 3, ≥
1
PENYELESAIAN:
2
= − 2 + 3
2
2
⇔ = ( − 1) −1 + 3 dan = − 2 + 3
= ( − 1) +2 = 2 − 2
′
2
− 1 = − 2
= 1 + − 2
;1 = 1 + − 2
Untuk = 3,
2
2
3 = − 2 + 3 ⟺ − 2 = 0
Matematika Dasar