Page 179 - Medicinal Chemistry Self Assessment
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3.  The calculated for difference in this pharmacokinetic property.

                                      Fenofibrate

                 4.  From an elimination NOT occur).

                                    O
                                                     O
                                               O
                        O
                       H
                                                        OH
                                                    CH
                                                C
                                              H
                                                       3
                                                3
                        Cl
                                                                                     B
                                    A

                                                             C               Gemfibrozil

            168    Medicinal Chemistry Self Assessment

                 5.  Provide a structural rationale for why oxidative O-dealkylation does not occur.
            5.  Provide a structural rationale for why oxidative O-dealkylation does not occur.
              Answer:
                Answer
                                                               1     2


                Oxidative O-dealkylation transformations occur with ethers that have at least one α-carbon (adja-
                cent carbon atom) with at least one hydrogen atom attached.  Evaluation of the ether found within

                the structure of fenofibrate reveals that one of the carbons (#1) attached to the ether oxygen atom
                is part of an aromatic ring. It does not have a hydrogen atom attached to it. Carbon #2, attached
                to two aliphatic alkanes (methyl groups) and a carboxylic acid, also does not have a hydrogen atom
                attached to it. Because neither of the α-carbons has at least one hydrogen atom attached to it, this
                ether is not subject to oxidative O-dealkylation.



            6.  Fenofibrate and gemfibrozil have dramatically different elimination half-lives (20–22 hours and 1.5
 1.14 and 2.14 (drug name – remove bold)
                hours respectively). Identify the possible metabolic transformations for gemfibrozil and provide a
                justification for the significant difference in this pharmacokinetic parameter.










               Fenofibrate                           Gemfibrozil

                Answer
 Letter “C” – add bold
                Possible phase I metabolic transformations:
                •   Benzylic oxidation (two different locations)*
                •   Oxidative O-dealkylation
                •   Aromatic hydroxylation (multiple)

                   *Note: Each benzylic hydroxyl group can be further oxidized to carboxylic acids.

                Possible phase II conjugation transformations:
                         C
                •   Glucuronide conjugation
                •   Amino acid conjugation (with glutamine, glycine, arginine or taurine)
 2.14 – remove bold from label

                The difference in aromatic substituents between the two drugs has a large impact on the number of
            B   potential phase I transformations that produce more water soluble metabolites. Oxidative O-
                              F
                dealkylation not only generates more water soluble products, but also splits gemfibrozil in half,
                       D
    A           causing drug deactivation. Based on this assessment, it is no surprise that there is a difference in the
                  C
                elimination half-lives of these two drugs and that gemfibrozil is eliminated much more rapidly.

                          E

                Fenofibrate


 2.14 – remove bold from label


            O               O     CH 3                              O               O
                                              Ester
                       O                    Hydrolysis                         O
                               O    CH 3                                               OH
                      H 3 C  CH 3                                             H 3 C  CH 3
 Cl                                                     Cl

                 Inactive                                           Active
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