Page 67 - Fiber Optic Communications Fund
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48                                                                Fiber Optic Communications


            R(r) and dR∕dr at the core–cladding interface leads to the following equations:

                                             C J ( a)= D K ( a),                          (2.50)
                                               1 m
                                                          1 m
                                                   1
                                                               2
                                                 ′            ′
                                            C  J ( a)= D  K ( a),                     (2.51)
                                             1 1 m  1     1 2 m  2
                  ′
            where denotes differentiation with respect to the argument. Dividing Eq. (2.51) by Eq. (2.50), we obtain the
            following eigenvalue equation:
                                                           ′
                                               ′
                                              J ( a)   K ( a)
                                               m  1      2  m  2
                                                     =                                        (2.52)
                                              J ( a)   K ( a)
                                                           m
                                                              2
                                                  1
                                               m
                                                         1
            where
                                                     √
                                                        2 2
                                                 =   k n −  2                             (2.53)
                                                 1
                                                        0 1
            and
                                                    √
                                                            2 2
                                                        2
                                                 =    − k n .                             (2.54)
                                                 2          0 2
            Note that in Eq. (2.52), the only unknown parameter is the propagation constant . It is not possible to solve
            Eq. (2.52) analytically. Eq. (2.52) may be solved numerically to obtain the possible values of .Itwouldbe
            easier to solve Eq. (2.52) numerically if we avoid differentiations in Eq. (2.52). This can be done using the
            following identities:
                                          ′
                                       aJ ( a)=−mJ ( a)+  aJ m−1 ( a),              (2.55)
                                                        1
                                             1
                                                     m
                                                              1
                                          m
                                                                     1
                                       1
                                          ′
                                       aK ( a)=−mK ( a)−  aK m−1 ( a).              (2.56)
                                             2
                                       2
                                                                      2
                                                      m
                                                              2
                                          m
                                                         2
            Using Eqs. (2.55) and (2.56) in Eq. (2.52), we obtain
                                            J m−1 ( a)   K m−1 ( a)
                                                 1
                                                         2
                                                                2
                                                    =−             .                          (2.57)
                                             J ( a)    1  K ( a)
                                                1
                                                               2
                                                             m
                                             m
            The propagation constants  obtained after solving Eq. (2.57) lie in the interval [k n , k n ]. It is convenient
                                                                             0 2  0 1
            to define the normalized propagation constant
                                                      2
                                                         2
                                                      ∕k − n 2 2
                                                         0
                                                 b =   2   2                                  (2.58)
                                                      n − n
                                                       1   2
            so that when  = k n , b = 0 and when  = k n , b = 1. For any guided mode of a step-index fiber, we have
                           0 2                   0 1
            0 < b < 1. Eq. (2.57) can be solved for various design parameters such as wavelength  and core radius a, and
            the numerically calculated propagation constant  can be plotted as a function of a specific design parameter.
            Instead, it is more convenient to define the normalized frequency
                                               √            √
                                                      2
                                                                2
                                                  2
                                          V = a   +  = k a  n − n 2
                                                           0
                                                  1   2         1   2
                                              2fa  2  2 1∕2
                                            =      (n − n )  ,                                (2.59)
                                                c   1   2
            where f is the mean frequency of the light wave. Using Eq. (2.7), Eq. (2.59) may be rewritten as
                                                      2a
                                                  V =     NA.                                 (2.60)
                                                       
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