Page 220 - MODUL X MIPA BIRU

2
a. 2 8 + 4
1
1
1

b. × ×

1
1
3
3
3
c. 3 24 − 2√3 + 2. + 2
9 4
Alternatif Penyelesaian
2
2
a. 2 log 8 + log 4 = log(8 × 4)
2
= log 32
5
2
= log 2
2
= 5. log 2
= 5.1
= 5
1
1
1

−1
b. log × log × log = log −1 × log −1 × log

= (− log ) × (− log ) × (− log )

= − log × log × log

= − log
= −1
1
1
3
3
3
c. 3 log 24 − log 2√3 + 2. log + log 2
9 4
2 9
1
3
3
3
3
= log 24 − log 2√3 + log ( ) +
9 4
1 9
24 × ×
3
= log 81 4
2√3
2
3
= log 3
2√3
3
= log 1
3√3
1
3
= log
3
32
3
3
−
= log 3 2
3
= −
2

3
8
3
2. Diketahui log 4 = dan log 5 = , tentukan log 20.
Alternatif Penyelesaian
3
8 log 20 = log 20
3
log 8
3 log(4×5)
= 3 log(4×2)
Modul Matematika Peminatan X 207