Page 174 - FUNDAMENTALS OF COMPUTER
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                   174                         Fundamentals of Computers                           NPP


                       Problem 3.24                                àíZ 3.24
                      Prove that:                                 {gÕ H$s{OE {H$:

                                                     A +  AB =  A + .  B
                  Solution:                                   hc:

                      Taking Left Hand Side as Y,                             Y

                                                      Y =  A +  A B .
                      Complement both the sides

                                                      Y =  A +  AB.
                      Applying De Morgan’s Laws

                                                    Y =  A AB.  .


                                                    Y =  A  .   A +  B  


                                                    Y =  A . ( A +  B )

                                                    Y =  A A +.  A B.

                                                    Y = 0 +  A  B .

                                                    Y =  AB.
                      Complement both the sides

                                                      Y =  AB.

                                                      Y =  A +  B
                                                      Y = A + B
                      Y = Right Hand Side, Hence we prove that
                                                      A +  AB =  A + .  B

                      Shortcut Method
                         Since,                     A + B.C = (A + B).(A + C)

                         Thus,                      A +   A  .B =  (A A).(A B)
                                                                 +
                                                                        +
                         But                          + AA 1
                                                          =
                         Therefore,                 A +    = A.B (A B)                    Hence Proved.
                                                               +
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