Page 314 - FUNDAMENTALS OF COMPUTER

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314 Fundamentals of Computers NPP

The block diagram showing two input ãbm°H$ S>m`J«m_ Xmo BZnwQ> ~m`Zar Zå~a A A A
3
2
Binary number A A A A and B B B B and A VWm B B B B Ed§ EH$ AmCQ>nQ> ~m`Zar Zå~a S 1
3
2
1
2
0
3
1
0
0
3
2
0
1
one output Binary number S S S S S can be S S S S Xem© ahm h¡ {Ogo {ZåZ àH$ma go ~Zm`m Om 4
0
1
2
4
3
drawn as: 3 2 1 0
gH$Vm h¡:
B3 B2 B1 B0 A3 A2 A1 A0
4- bit Binary Adder
S4 S3 S2 S1 S0
Problem 3.85 àíZ 3.85
Draw and explain 6-bit Binary Adder 6-{~Q> Ho$ ~mBZar ES>a H$mo g_PmAmoŸ&
Solution: hc:
A 6 bit Binary Adder is capable of adding EH$ 6-{~Q> H$m ~mBZar ES>a Xmo g§»`mAm| H$m `moJ
two 6-bit Binary Numbers. Suppose The input àXmZ H$aVm h¡Ÿ& _mZm {H$ `o g§»`mE± A A A A A
Binary numbers are A A A A A A and B B 4 5 4 3 2 1
2
0
1
5
4
5
3
B B B B , then the output Binary number can A VWm B B B B B B h¡Ÿ& AV… BZHo$ `moJ H$mo S 6
1
0
0
2
4
5
3
3
0
1
2
be represented as S S S S S S S . This adder S S S S S S {bIm Om gH$Vm h¡Ÿ& Bg n[anW hoVw
3
4
1
0
2
5
4
0
6
5
3
1
2
will need one half Adder and five full Adders: EH$ hm\$ ES>a VWm nm±M \w$b ES>a n`m©á hm|JoŸ&
A5 A4 A3 A2 A1 A0
B5 B4 B3 B2 B1 B0
F.A F.A F.A F.A F.A H.A
C6 C5 C4 C3 C2 C1
S6 S5 S4 S3 S2 S1 S0
At the block diagram level the input binary ãbm°H$ S>m`J«m_ H$s ghm`Vm go BZnwQ> VWm AmCQ>nwQ>
numbers and output binary number can be ~mBZar g§»`mAm| H$mo Bg àH$ma ~Vm gH$Vo h¢…
shown as: