Page 47 - Modul Matematika Peminatan Kelas X KD 3.2 (Vektor)
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Modul  Matematika Peminatan Kelas X KD 3.2




                                       3 = 5 →    = 8
                                     2−
                                                 2
                                       2 = −1  →    =1   ...............................................................................................2
                                                   3
                                     3−
                                                                    ⃗⃗⃗⃗⃗
                                                             ⃗⃗⃗⃗⃗
                                    Jadi koordinat titik S agar      = −     adalah S(0, 8, 1)............................2

                                                                   0  
                                                                  
                                                                      

                                                              ⃗
                            3.  a.  Vektor satuan searah vektor      =  0  
                                                                  
                                                                     
                                                                   1 
                                                 ⃗
                                                             2
                                                                  2
                                                                          2

                                                      ⃗

                                    Panjang vektor    = |  | = √0 + 0 + (−1) = √1 = 1
                                                                           0  
                                                                             
                                                                            0  
                                                                           1     0   
                                                                                   
                                                                          
                                                                              
                                                             ⃗
                                                                                       
                                    Vektor satuan searah vektor    =     =     ⃗⃗   =  =    0 ……………….5

                                                                     |   ⃗⃗ |  1
                                                                                      
                                                                                    1 
                                                                   −1
                                                              ⃗
                                                              ⃗
                               b.  Vektor satuan searah vektor      = ( 1 )
                                                              ⃗
                                                                   −1

                                                                 2
                                                                      2
                                                                               2

                                   Panjang vektor    = |  | = √(−1) + 1 + (−1) = √3
                                                                            −1
                                                                           ( 1 )      −1       −√3
                                                                                             1
                                   Vektor satuan searah vektor    =     =      =  −1  =  1  ( 1 ) = (  √3 )

                                                                      |   ⃗⃗ |  √3  √3       3
                                                                                      −1       −√3
                                                                                                                                                     ……………….5

                                                                           Pembilang dan
                                                                         penyebut dikalikan
                                                                                √3










                                   ⃗⃗⃗⃗⃗
                               c.       dengan  C (3 , -2 , 1) dan D (2 , -2 , 1)
                                                   2       3      −1
                                   ⃗⃗⃗⃗⃗
                                        =    −     = (−2) − (−2) = ( 0 )
                                                   1       1       0
                                                ⃗⃗⃗⃗⃗
                                          ⃗⃗⃗⃗⃗
                                                                  2
                                                             2
                                                                       2
                                   Panjag      = |    | = √(−1) + 0 + 0 = √1 = 1
                                                                           −1
                                                                          ( 0 )  −1
                                                                        
                                                              ⃗⃗⃗⃗⃗
                                   Vektor satuan searah vektor      =  ⃗⃗⃗⃗⃗   =  0  =( 0 )……………….5
                                                                    ⃗⃗⃗⃗⃗
                                                                    |    |  1
                                                                                 0






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