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188                                                                Chapter 4


                              
                                = −2  ∆       [(m/m) ⋅ Ω ⋅ A  =  V]
                                           0 
                                                             �                (4.83)
                                          ∆ = � 
        Formally, the equivalent magnetic current magnitude is frequency dependable, but it does not
        change the main result: at each frequency the structure of electric and magnetic fields created
        by the electrically small loop antenna and magnetic dipole are identical.

        The following from this statement the near-field structure around the loop is displayed in Figure
        4.3.5c. These  drawings  are the replica of the  plot  in Figure 4.3.1a adjusted through the
        replacement  ⟹ ,  ⟹ −. When the currents and dimensions are chosen according to
        (4.83), the infinitesimal electric dipole and a small loop antenna are defined as dual sources
        since the magnetic field of one is identical to the electric field of the other and vice versa. More
        conclusions can be made from this analogy:

                                               1.  The total near-field structure consists of
                                               two components of magnetic field  ,  , and
                                                                            
                                                                               
                                               single  azimuthal  component of electric
                                               field    (see Figure 4.3.6  and compare  to
                                                    
                                               Figure 4.3.1b).
                                               2.  In far-field area only two  orthogonal
                                               components of EM  fields are left  as Figure
                                               4.3.4b demonstrates, one magnetic   and one
                                                                            
                                               electric     (compare to 4.3.5c). The radial
                                                       
                                               component   becomes so insignificant that it
                                                          
                                               can be neglected in far-field area.
            Figure 4.3.6 Loop field components in   3.  Both  non-zero  components  are
                   spherical coordinates
                                               tangential to the radiation spherical phase and
                                               magnitude  waveform and thus represent  the
            transverse wave propagating in the radial direction.
        4.  There is no radiation at all along  the  z-axis,  which  would correspond to the radiation
            directly overhead the magnetic dipole and loop. The radiation is maximum in XY-plane that
            is the horizontal / azimuthal plane. Now any reference plane parallel to XY-plane contains
            the electric component   only. Therefore, the magnetic dipole and loop is omnidirectional
                               
            in the E-plane.
        5.  The patterns in XZ- or YZ-plane are bi-directional (see (4.82) and Figure 4.3.5) and have a
            shape reminiscing the infinity symbol ∞ or lying figure 8. Now any reference plane parallel
            to XZ- or YZ-plane and passing through the z-axis contains the magnetic component  
            only. Therefore, for the magnetic dipole and loop antenna vertical / elevation planes are H-
            planes.
        6.  As expected and according to (4.82) Poynting’s vector of the harmonic wave radiated by
            the loop antenna points out the radial direction, satisfies the radiation condition (3.72)  and
            equals to


                                                                      2
                                                                            )    (4.84)
                       1               ∗         ∗            2  sin    2
                    = �−  � × (  ) =    ⁄ =  �  �  0  ( 
                                                   2
                                               
                                            0
                                       
                            0 
                                                 
                                                        0
                                     0
                       2                                     2  2  2
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