Page 22 - Bahan Ajar Bismillah(2)
P. 22

Misal:    = 5 sin    →    = 5 cos   
                                               ′
                                                                      ′
                                                         =             →    = −         
                                 ′     −       ′
                         ′
                             =
                                      2
                               5 cos     ∙  cos     −  5 sin     ∙  −sin   
                            =
                                                  2
                                              cos   
                                    2
                                               2
                               5 cos    +  5 sin   
                            =
                                        2
                                     cos   
                                              2
                                     2
                               5 (cos    +  sin   )
                            =
                                         2
                                     cos   
                               5 (1)
                            =
                                  2
                               cos   
                                 5
                            =
                                  2
                               cos   
                                    2
                            = 5 sec   
                                                  1
                                                ′
                     3.  Carilah         dan nilai          jika diketahui        =    sec   .
                                                                              3
                                 ′
                                                  3
                        Penyelesaian
                                     3
                                  =    sec   
                                       2
                            (  )   = 3            +                ∙           
                          ′
                                                 3
                           1          1          1       1         1            1
                                          2
                                                             3
                         ′
                           (   )  = 3(   )        (   ) + (   )         (   ) ∙         (   )
                           3          3          3       3         3            3
                                    1            1
                                        2
                                                     3
                                 =      ∙  2  +         ∙  2  ∙  3
                                    3            27
                                    2        2
                                        2
                                                 3
                                 =     +           3
                                    3       27
















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