Page 249 - Linear Models for the Prediction of Animal Breeding Values 3rd Edition
P. 249

Calculating m and the residual regression coefficient

        From Eqn 13.14, the model for the jth row of the contingency table may be written as:
            y  = x′ b  + z′ u  + e
             2j  2j 2   2j 2  2j
        where x′  and z′  are vectors j of the X  and Z , respectively.  Similarly, observations
               2j     2j                  2      2           .
        for trait 1, corresponding to the jth row of the contingency table, may be modelled as:
            y  = x′ b  + z′ u  + e
             1j  1j 1   1j 1  1j
        Let m  be the expectation of y  given b, u and y . Thus:
             j                    2j             1j
            m  = E(y | b , b , u , u , y ) = x′ b  + z′ u  + E(e | e )     (13.20)
             j     2j  1  2  1  2  1j  2j  2  2j 2   2j  1j
        given that e  is only correlated with e . Assuming e  and e  are bivariately normally
                  2j                     1j          2j    1j
        distributed:
                         21
            E(e  | e  ) =  s e(, )  e ()
               2j  1j    2    1j
                         e1
                        s
                         ⎛   ⎞
                     =  r 12 ⎜  s e2 ⎟  e
                         ⎝  s e1 ⎠  1j                                     (13.21)
                2                                and r  are the residual covariance and
                ei
        where s  is the residual variance of trait i, s ei,k  ik
        correlation between traits i and k, and s  is the residual standard deviation of the ith
                                           ei
        trait. Similarly:
                                               2
                                                      2
            var(y | b , b , u , u , y ) = var(e | e ) = s (1 − r )
                2j  1  2  1  2  1j     2j  1j  e2     12
        Since the unit of the conditional distribution of the underlying trait, given b , b , u , u
                                                                        1  2  1  2
        and y  is the standard deviation, then from the above equation:
             1j,
               =    1
             e2
            s         2
                  ( 1−  r )
                      12
        Therefore, Eqn 13.21 can be written as:
                        ⎛  1 ⎞  1
            E(e  | e  ) = r 12 ⎜     e  = be                               (13.22)
               j 2  j 1    e1 ⎠ ⎟  2  j 1   j 1
                        ⎝ s    1 −  r 12
        In general, Eqn 13.20 can be expressed as:
            m = X b  + Z u  + be
                 2 2   2 2    1
              = X b  + Z u  + b(y − X b − Z u )                            (13.23)
                 2 2    2 2    1    1 1   1 1
        The above equation may be written as:
            m = X (b  − bHb ) + Z (u  − bu ) + by *
                 2  2     1     2  2   1     1
            m = X t + Z n + by *                                           (13.24)
                 2    2      1
        with the solutions of factors affecting calving difficulty corrected for the residual
                                                                    *
                                            *
        relationship between the two traits and y  = (y − X b − Z u ) or y  may be calcu-
                                            1    1    1 1   1 1     1
        lated as:
            y =  y (  − y  ), where  is the mean of  y .
             *
                              y
             1    1   1        1             1
        Analysis of Ordered Categorical Traits                               233
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