Page 251 - Linear Models for the Prediction of Animal Breeding Values 3rd Edition
P. 251

(Continued)
            Factor                  Number     Birth weight (kg)  Frequency CD a
            Sex of calf       M       25             –               0.360
                              F       22             –               0.091
            Sire of heifer    1       10           40.55             0.000
                              2        7           42.99             0.286
                              3        6           40.53             0.000
                              4        4           45.38             0.500
                              5       11           45.46             0.364
                              6        9           43.43             0.333
            a Frequency of calving difficulty.
            The following sire–maternal grandsire relationship matrix was assumed among
        the sires:
                              Bull    Sire   Maternal grandsire

                              1        0            0
                              2        0            0
                              3        1            0
                              4        2            1
                              5        3            2
                              6        2            3


            The inverse of the sire–maternal grandsire relationship matrix obtained for the
        above pedigree using the rules in Section 2.5 is:

                 ⎡  1.424  0.182  −0.667  −0.364    0.000   0.000⎤
                 ⎢                                 − 0.364 −     ⎥
                                               7
                 ⎢  0.182  1.818   0.364  −0.727            0.727 ⎥
                  − ⎢  0.667  0.364  1.788  0.000 − 0.727  − 0.364⎥
              −1
            A  = ⎢                                               ⎥
                               7
                 ⎢ − 0.364 − 0.727  0.000   1.455   0.000   0.000 ⎥
                 ⎢  0.000 − 0.364 − 0.727  0.000    1.455   0.000 ⎥
                 ⎢                                               ⎥
                 ⎣ ⎢  0.000 − 0.727  − 0.364  0.000  0.000  1.455⎥ ⎦
                       0
        The residual variance (s ) for BW was assumed to be 20 kg  and the residual correla-
                             2
                                                            2
                             e1
        tion (r ) between BW and CD was assumed to be 0.459. Therefore, from Eqn 13.20,
              12
        b equals 0.1155. The matrix G assumed was:
                æ0.7178    0.1131 ö
            G =  ç               ÷
                è 0.1131   0.0466 ø

        Therefore, from Eqn 13.16:

                                                            0 7178 0 0302⎞
            G =  ⎛ 1       0 ⎞ ⎛0 7178 0 1131 1.  . .  ⎞ ⎛  −0 1155.  ⎞ ⎟ ⎠  =  ⎛ .  . .  ⎟
                                            ⎟ ⎜
                                                           ⎜
                 ⎜
                            ⎟ ⎜
              c
                                                            0 0302 0 0300⎠
                                            ⎠ ⎝
                 ⎝
                            ⎠ ⎝0 1131 0 0466 0.
                                                           ⎝ .
                  −0 1155 1.
                                                  1 1
        Analysis of Ordered Categorical Traits                               235
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