Page 6 - PJ Struktur Aljabar_Kelompok Ke 5_PSPM C 2019
P. 6
Contoh
M ( )
Temukan orbit dari !
Penyelesaian
S 1 = {x A | (1,x) f} = {x A| ∋ x = ( )}
( ) = 5; ( ) ; ( ) ( ) Diperoleh S 1 = {1,5,7,8}
S 2 = {x A | (2,x) f} = {x A| ∋ x = ( )}
( ) = 6; ( ) ; ( ) Diperoleh S 2 = {2,3,6}
S 4 = {x A | (4,x) f} = {x A| ∋ x = ( )}
( ) = 4; Diperoleh S 4 = {4}
Terlihat bahwa S 1 S 2 S 4 A dan S 1 S 2 S 4=
3