Page 124 - Fiber Optic Communications Fund
P. 124

Lasers                                                                             105










                        Longitudinal modes












                                  c/2nL                                   Frequency,  f

                                 Figure 3.13 The output spectrum of a Fabry–Perot laser.



            Eq. (3.31) provides the evolution of the optical intensity as a function of the propagation distance. Some-
           times, it is desirable to find the evolution of the optical intensity as a function of time. To obtain the time
           rate of change of the optical intensity, we first develop an expression relating optical intensity  and energy
           density u. The optical intensity is power P per area S, which is perpendicular to the direction of propagation,

                                                       P
                                                    =  .                                   (3.46)
                                                       S
           The power is energy ΔE per unit time,
                                                      ΔE
                                                  P =    ,                                  (3.47)
                                                      Δt
           where Δt is a suitably chosen time interval. Combining Eqs. (3.46) and (3.47), we find

                                                      ΔE
                                                   =    .                                  (3.48)
                                                      SΔt
           Fig. 3.14 shows the optical intensity at z and z +Δz. The number of photons crossing the area S at z +Δz
           over a time interval Δt is the same as the number of photons present in the volume SΔz if

                                                  Δz = Δt,                                (3.49)
           where  is the speed of light in the medium. For example, if Δt is chosen as 1 ns, Δz is 0.2m assuming
                   8
            = 2 × 10 m∕s. Using Eq. (3.49) in Eq. (3.47), Eq. (3.46) becomes
                                                   ΔE
                                                =      = u,                              (3.50)
                                                   SΔz
           where u is the energy density or energy per unit volume. Since I ∝ u, Eq. (3.32) can be written as
                                                  du
                                                     = gu.                                  (3.51)
                                                  dz
   119   120   121   122   123   124   125   126   127   128   129