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Transmission System Design                                                         315


           To have negligible ISI, the pulse at the receiver should remain within its bit slot. The commonly used criterion
           is [4]
                                                  ≤ T ∕4,                                 (7.99)
                                                  L
                                                       B
           where T is the bit interval. Using Eqs. (7.98) and (7.99), we obtain
                 B
                                            [  4    2 2  ] 1∕2
                                             4 +  L
                                               0   2      B ≤  1 .                         (7.100)
                                                4 2         4
                                                  0
                                            opt                 opt  √
           If we choose the optimum pulse width T  , the corresponding   is   L∕2. Using this value of  in
                                            0                   0      2                      0
           Eq. (7.100), we find [4]
                                                           1
                                                      1∕2
                                               B(| |L)  ≤  .                             (7.101)
                                                  2
                                                           4
           For fixed | |, as the bit rate increases linearly, the maximum transmission distance decreases as L −1∕2 .To
                    2
           undo the pulse broadening due to fiber dispersion, a DCF may be used (see Chapter 2) or it may be com-
           pensated in the electrical domain using a DSP (see Chapter 11). In some applications such as metro/access
           networks, it would be expensive to use DCF or coherent receivers. For such applications, Eq. (7.101) provides
           a simple design rule relating the reach, bit rate, and dispersion.


           Example 7.3
           A fiber-optic system is upgraded to operate at 10 Gb/s from 2.5 Gb/s. The maximum transmission distance at
           2.5 Gb/s at a BER of 10 −9  was 100 km. Find the corresponding distance at 10 Gb/s. Assume that the trans-
           mission fiber is unchanged and the penalty due to fiber dispersion is the same in both systems.

           Solution:
           Let

                                          B = 2.5Gb/s, B = 10 Gb/s,
                                           1           2
                                                L = 160 km.
                                                 1
           From Eq. (7.101), we have
                                                  1∕2     1∕2
                                               B L   = B L  ,
                                                1 1     2 2
                                                 L = 10 km.
                                                  2




           7.4  ASE-Induced Limitations
           To transmit an optical signal over a long distance, amplifiers have to be introduced along the transmission
           line. Otherwise, the received power could be too low to detect. In Section 7.2.1, we found that 9 photons/bit
                                                                  −9
           is required at the receiver for a PSK signal to achieve a BER of 10 . The number of photons/bit at the
           receiver can be increased by introducing amplifiers. However, amplification by stimulated emission is always
           accompanied by ASE, which enhances the noise in the system. In a long-haul fiber-optic system consisting
           of a chain of amplifiers, ASE builds up over many amplifiers, which degrades the transmission performance.
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