Page 51 - MODUL TERMOKIMIA

Contoh :

Diketahui harga energy ikatan rata-rata :
C-H = 415 kj C-Cl = 328 kj

Cl-Cl = 242,6 kj H-Cl = 431 kj
Tentukan ∆Hreaksi CH4(g)+Cl2(g)→CH3Cl(g)+HCl(g)

H H

H C H + Cl Cl H C Cl + H Cl

H H

∆H = [4)C-H) + 1(Cl-Cl)] – [3(C-H) + 1(C-CL) + 1(H-Cl)
= (4(415) + 242,6) – (3(415) + 328 + 431) kj

= (1160 + 242,6) – (1245 + 759) kj
= (1902,6 – 2004) kj

= -101,4 kj mol -1

MODUL TERMOKIMIA 42
MODUL TERMOKIMIA 42