Page 13 - KIII - RAZONAMIENTO MATEMATICO 3SEC

Razonamiento Matemático 3° Secundaria

PROBLEMAS RESUELTOS

1. Si : x = 2x − 6 Resolución

x + 2 = 4x + 4 x + 2 = 2 x + 2 − 6 = 4x + 4
x + 2 = 2x + 5
Halle: E = 8 − 51 8 = 6 + 2 = 2 6 5 = 17
( ) +

+
1 = − 1 2 = 2 ( 1− ) + 5 = 3
 E = 17 − 5 3 2
( ) =
Rpta.: 2

2
2. Si : n = (n + 1 ) + 4 Resolución
2
a#b = (  a#b ) 1−  + 4 = 4a

a#b = 4a
a#b = 4a − 4 + 1
x = 50#65 = 4 ( 50 − 4 + 1 15
)
=
Halle: x = 50#65 Rpta.: 15

3. a @b = 3 a − b Resolución
2
3
2
)
Halle: E = (4@27 )(6 2 @512 4@27 = 16 @3 = 16 − 3 = 7
3
2
6 2 @512 = 72 @8 = 72 − 8 = 8
E = 7@8 = 49 @2 = 49 − 2 = 45
3
2
Rpta.: 45

4. Si: a #b 2 ( b #a 2 ) − ab Resolución

2

3 1/4 #2 a #b = 2 2 ( a #b 2 ) ba−   − ab
Halle: x =
6 a #b = 4 ( a #b 2 ) 2ba ab− −
2

2
3 ( a #b 2 ) = 3ab  a #b = ab
4 3 #2 = 3 # ( 2 ) 2
de “x”: 3 #2 = 3  2 = 6
4
6
x = = 1
6
Rpta.: 1

5. Si : x = 2 ( x 16− ) Resolución


x + 3 = 8x x + 3 = 2 x + 3 − 16   = 8x

x + 3 = 4x + 16
Halle: E = 4 − 2 2 4 = 1 3 = 4 ( ) 1 + 16 = 20
+

+
2 = − 1 3 = 4 ( 1− ) + 16 = 12
)
 E = 20 − 2 ( 12 = − 4
Rpta.: 4

3 Bimestre -150-
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