Page 27 - E Modul Vektor (Revisi)

Modul Matematika Peminatan X

6
⃗⃗⃗⃗⃗
= (0)
0

= −
⃗⃗⃗⃗⃗
4 −2
= ( 3 ) − ( 3 )
⃗⃗⃗⃗⃗
−1 5
6
= ( 0 )
⃗⃗⃗⃗⃗
−6

6 6
⃗⃗⃗⃗⃗ ⃗⃗⃗⃗⃗
. = (0) . ( 0 )
0 −6
⃗⃗⃗⃗⃗ ⃗⃗⃗⃗⃗
. = 36 + 0 + 0 = 36

| | = √6 + 0 + 0
⃗⃗⃗⃗⃗
2
⃗⃗⃗⃗⃗
| | = 6

⃗⃗⃗⃗⃗
| | = √6 + 0 + (−6)
2
2
⃗⃗⃗⃗⃗
| | = 6√2

⃗⃗⃗⃗⃗ ⃗⃗⃗⃗⃗
.
=
⃗⃗⃗⃗⃗ ⃗⃗⃗⃗⃗
| || |

36
=
6 .6√2
1
= √2
2
1
= cos √2
2
= 45°

Jadi besar sudut adalah 45°.

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