Page 185 - Fiber Optic Communications Fund
P. 185

166                                                               Fiber Optic Communications


                                         0     1      0      1      0     0      0
                                   +1
                       Polar NRZ data  b'(t)                                           t

                                    –1



                                   +1
                         Differentially
                         encoded data   b(t)                                           t

                                    –1


                                   +2


                        Duobinary data  m(t)                                           t


                                    –2
                                        T b
                                           Figure 4.29  Duobinary encoding.



                                                      p(t)    p(t ‒ T b )


                                                 1







                                                                                     t
                          –3T b  –2T b    –T b     0      T b    2T b     3T b   4T b

            Figure 4.30  A duobinary pulse in the 0th bit slot interacts only with a pulse in the first slot at t = T . At any other
                                                                                        b
            sampling instants, p(t)= 0.


            and is shown in Fig. 4.30. The pulse p(t) is used to transmit a ‘1’ and −p(t) is used to transmit a ‘0’. As can
            be seen from Fig. 4.30, pulses p(t) and p(t − T ) do not interfere at any sampling instants except at t = T .
                                                  b                                              b
            Although pulses interfere at other times, this does not lead to performance degradations since the decisions
            are made based on the sample values at t = nT . The duobinary signal may be written as
                                                 b
                                                    ∞
                                                    ∑
                                             m(t)=     b p(t − nT ),                          (4.92)
                                                                b
                                                        n
                                                   n=−∞
   180   181   182   183   184   185   186   187   188   189   190