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Transmission System Design                                                         307


                                               ∘
           intensity noise (RIN), and imperfections in 90 hybrid. In the presence of shot noise, Eqs. (5.109) and (5.110)
           are modified as (with  = 0, Δ = ∕2)
                             IF
                                    R       2       2
                               I =   {A |s(t)| + |A LO | + 2A A  Re{s(t)}}+ n shot +,       (7.30)
                                        r
                                                         r LO
                                +
                                    2
                                    R       2       2
                               I =   {A |s(t)| + |A LO | − 2A A  Re{s(t)}}+ n shot −,       (7.31)
                                −
                                                         r LO
                                        r
                                    2
                                                                  −
                                                           +
           where n shot + and n shot − are the shot noise introduced by PD and PD , respectively. Subtracting Eq. (7.30)
           from Eq. (7.31), we have
                                  I = I − I = 2RA A  Re{s(t)} + n shot + − n shot −.        (7.32)
                                      +
                                          −
                                                 r LO
           Let
                                             n shot  = n shot + − n shot −.                 (7.33)
           Since n shot + and n shot − are statistically independent, the variance of n shot  is the sum of the variances of n shot +
           and n shot −:
                                             2  =  2  + +  2  −
                                             shot  shot  shot
                                                = 2qI B + 2qI B .                           (7.34)
                                                    + e
                                                            − e
           Let
                                                 P   = A 2  ,                               (7.35)
                                                  LO    LO
                                                       2 2
                                                P (t)= A s (t).                             (7.36)
                                                       r
                                                 r
           Here, P LO  and P are the LO and receiver power, respectively. First consider the OOK. For bit ‘1’ (s(t)= 1
                        r
           within the bit slot), the mean and variances of the current are
                                                     √
                                              I = 2R P P    ,                               (7.37)
                                               1        1r LO
                                                        2
                                                  P = A ,                                   (7.38)
                                                   1r   r
                                           2  = 2qI B + 2qI B ,                           (7.39)
                                           1,shot   1+ e     1− e
                                            R  {           √      }
                                       I 1+  =  P + P LO  + 2 P P   ,                       (7.40)
                                                              1r LO
                                                1r
                                            2
                                            R  {           √      }
                                       I  =    P + P    − 2 P P     .                       (7.41)
                                       1−       1r   LO       1r LO
                                            2
           Using Eqs. (7.40) and (7.41), Eq. (7.39) becomes
                                            2
                                              = 2qB R(P + P   ).                          (7.42)
                                            1,shot   e   1r   LO
           The total noise variance of ‘1’ is
                                       2
                                       =  2  +  2
                                       1    1,shot  1,thermal
                                         = 2qB R(P + P LO )+ 4k TB ∕R .                     (7.43)
                                                                 e
                                                  1r
                                                                    L
                                              e
                                                             B
           Similarly, for bit ‘0’, we have
                                                   I = 0,                                   (7.44)
                                                    0
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