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502                                                               Fiber Optic Communications


                            4
                                                                              w/o eq
                                                                              w eq
                            2

                          Phase (rad)  0






                           *2



                           *4
                             0         500        1000       1500       2000       2500
                                                      Sample #

            Figure 11.5  Phase vs. sample number for the back-to-back case with no phase modulation. Parameters: Tx laser
            linewidth = LO linewidth = 50 kHz, f = 200 MHz.
                                        IF

            or
                                           ̂ f =  −1    Arg[(y y ∗  ) ].                     (11.27)
                                                                  M
                                           IF
                                                2T samp M  l l−1
                                                                     ̂
            However, in the presence of n and Δ , the estimated frequency offset f fluctuates from symbol to symbol.
                                    l      l                         IF
            Since n and Δ −Δ  are zero-mean random variables, the fluctuations can be minimized if we average
                  l       l    l−1
            over N samples,
                                                         [          ]
                                                           N
                                                −1        ∑     ∗  M
                                         ̂
                                        f =           Arg    (y y  )  .                      (11.28)
                                         IF
                                                               l l−1
                                             2T samp M   l=1
              The frequency estimate f ̂ IF  gets better as the block size N increases, as long as f ̂ IF  remains constant over
                                                                                 ̂
            the block size. The IF is removed by multiplying y by exp (−iΔ), where Δ =−2f T  . The solid and
                                                                                 IF samp
                                                     l
            broken lines in Fig. 11.5 show the phases with and without IF equalization, respectively, when the phase
            modulation is turned off. In this example, we consider the back-to-back case with no fiber-optic channel
            between transmitter and receiver. When IF equalization is not used, the phase increases constantly because
            of the term 2f t in Eq. (11.9). However, the Arg(⋅) function can not distinguish phases that differ by 2
                         IF l
            and produces results in the [−, ] interval. When the IF equalization is used, from Fig. 11.5, we see that
            the phase fluctuations are quite small, indicating that the equalizer is effective in removing IF. These phase
            fluctuations after the IF removal are due to laser phase noise. Equalization of the phase noise is discussed in
            the next section.
              Fig. 11.6(a) and (b) shows the constellation diagrams before and after the IF removal, respectively, for the
            QPSK signal. Before the IF removal, the phase varies almost uniformly over the range of 0 to 2.After the
            IF removal, the phase is close to one of the transmitted phases 0, ∕2, ,3∕2.
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