Page 152 - FUNDAMENTALS OF COMPUTER

NPP

152 Fundamentals of Computers NPP

Solution : hc :
(a) The given decimal number is 46. 31 (a) Xr JB© g§»`m 46.31 H$m nyUmªH$ dmbm {hñgm
Consider the integer part : 46 b|…

4 46 2
4 11 3
4 2 2
0

Thus, (46) = (232) 4
10
Now consider the fractional Part : A~ Am§{eH$ {hñgo H$mo bo …
. 31 × 4 = 1.24 1
.24 × 4 = 0.96 0
.96 × 4 = 3.84 3
.84 × 4 = 3.36 3
Thus, (.31) = (.1033) 4
10
Combining both the results : XmoZm| ^mJm| Ho$ n[aUm_m| H$mo {_bmZo na …
(46.31) = (232.1033) 4
10
(b) The given decimal number is (82.24) 10 (b) Xr JB© g§»`m 82.24 H$m nyUmªH$ dmbm {hñgm

Consider the Integer Part : 82 b|…
7 82 5
7 11 4
7 1 1
0
Thus, (82) = (145) 7
10
Now consider the fractional part : A~ Am§{eH$ ^mJ H$mo b| …
.24 × 7 = 1.68 1
.68 × 7 = 4.76 4
.76 × 7 = 5.32 5
.32 × 7 = 2.24 2
Thus, (.24) = (.1452) 7
10
Combining both the results : XmoZm| ^mJm| Ho$ n[aUm_m| H$mo {_bmZo na …
(82.24) = (145.1452) 7
10