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                     238                         Fundamentals of Computers                          NPP

                        POS Form  Solution:  Take the  same         POS \$m_© gm°ë`yeZ: 0 Ho$ g_yh ~ZmH$a POS Ho$
                    Karnaugh map. Use ‘0’ to form pairs, quads etc.  ê$n _| ì`§OH$ àmßV {H$`m Om gH$Vm h¡:
                                                  A  B C  00  01    11     10


                                                   0    0     0      0     1


                                                   1    1     0      1     1

                        The simplified expression in POS Form can   VrZ no`am| go àmßV POS ê$n Bg àH$ma àmßV hmoJm:
                    be written as:  F =  (A +  B ) (A.  + C ) (B.  +  C )  F =  (A +  B ) (A.  + C ) (B.  +  C )

                    Implementation using Universal Gates        `y{Zdg©b JoQ>m| H$s ghm`Vm go Bpåßb_|Q>oeZ
                        There are two types of universal Gates.     My±{H$ Xmo àH$ma Ho$ `y{Zdg©b JoQ> hmoVo h¢, Bg{bE Xmo
                    Therefore we can implement the simplified ex-  àH$ma H$m Bpåßb_|Q>oeZ {H$`m Om gH$Vm h¡:
                    pression in two ways:
                        (i)  NAND  Implementation.                  (i)  NAND  Implementation.
                        (ii) NOR  Implementation.                   (ii) NOR  Implementation.
                        Consider one by one.                    A~ h_ BÝh| EH$-EH$ H$aHo$ g_PVo h¢Ÿ&
                    (i) NAND Implementation: For this purpose   (i) NAND Bpåßb_|Q>oeZ: Bg hoVw SOP ê$n H$m Cn`moJ
                        use SOP Form of the solution. It will pro-  H$aZm Mm{hE {Oggo n[anW gabVm go ~Zm¶m Om
                        vide an economical design. The SOP Form     gHo$JmŸ&
                        of the solution is

                                                     F =   C . B  +  B . A  +  C . A
                        First Draw the Basic Gate Circuit:          gd©àW_ Cnamoº$ g_rH$aU go _yb^yV JoQ> `wº$ n[anW
                                                                ~ZmE:
                                         A        B        C
                                                                C







                                                                                  F






                        (Note : We have  not drawn  B  and  A       (Ü`mZ X| {H$ B  d  A Zht ~ZmE JE h¢ Š`m|{H$ do
                    since these are not needed in the expression.).  ì`§OH$ _| Zht h¢Ÿ&) AND H$mo NAND _| ~XbZo hoVw
                    Now convert each AND Gate into NAND Gate    BgHo$ AmCQ>nwQ> na ~~b bJmE VWm àË`oH$ ~~b H$mo
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