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PENGUJIAN BAHAN 2 (BETON ASPAL)

P E RC O BAAN P RD
B S 598 P a rt 104 (1989 )
SPESIFIK A SI T A N G G A L
A G REG A T D IK ERJA K A N
A SPA L D IPERIK SA
N o . a b c d e f g h i j k l m n o p q r
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2
RA T A 2

1

2
RA T A 2

1

2
RA T A 2

G mm * : K a G mm : B j. agregat bulk : B j. agregat eff. : B j. aspal : A bs. A spal :

Keteran g an :
a = tin g g i b r iket (m m ) h = b erat isi (d /g ) j= % ron g g a th d . ag reg at 1 0 0 -(h * (1 0 0 - c))/b j.b u lk) p = keleleh an (m m )
b = % asp al terh ad ap ag reg at i = b erat jen is m aksim u m (teoritis) k = % ron g g a th d . cam p u ran 1 0 0 -(1 0 0 x(h /i) q = H asil b ag i M arsh all
c = % asp al terh ad ap cam p u ran 100 l = % ron g g a terisi asp al (1 0 0 x(j- k))/j o / p (kg /m m )
d = b erat kerin g (g r) % ag reg at % asp al m = p em b acaan arloji stab ilitas r = Kad ar asp al eff. (% )
e = b erat d alam kead aan jen u h (g r) f BJ. ag reg at BJ. asp al n = stab ilitas (m x kon versi) o = c-((Ab s.asp al/1 0 0 )* (1 0 0 - c))
= b erat d alam air (g r) stab ilitas (kg )
g = isi (e- f) n x koreksi b en d a u ji

* G mm : d iten tu kan d en g an cara AAS H TO T 2 0 9 * * BJ. E ff Ag r = (1 0 0 - P b ) * * * Ab sorp si asp al terh ad ap total ag reg at =
p ad a kad ar asp al op tim u m p erkiraan (P b ) (1 0 0 /G mm )-(P b /BJ.asp al) 1 0 0 x (BJ. E ff. ag r - BJ. Bu lk ag r) x BJ. Asp
P b = 0 ,0 3 5 (% CA)+ 0 ,0 4 5 (% FA)+ 0 ,1 8 (% FF)+ K (BJ. E ff. ag r x BJ. Bu lk ag r)
K = 0 ,5 - 1 u n tu k Laston ; 2 - 3 u n tu k Lataston

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