Page 250 - FUNDAMENTALS OF COMPUTER
P. 250

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                   250                         Fundamentals of Computers                           NPP


                      When we put a bubble at each AND gate,      àË`oH$ AND JoQ> Ho$ AmCQ>nwQ> na ~~b bJmH$a
                  we  will obtain  five NAND  Gates and  one  NAND JoQ> àmßV {H$`m J`m h¡ Ÿ& Bggo EH$ ~~ëS> OR
                  bubbled OR Gate. Four NOT Gates can be re-
                  placed  by shorted  NAND Gates and the      JoQ> ñdV… àmßV hmoJm Ÿ& Bgo ^r NAND _| ~Xb gH$Vo
                  bubbled OR can be replaced by NAND Gate.    h¢ Ÿ& gmao NOT JoQ>m| Ho$ ñWmZ na NAND JoQ> ~ZmZo na:
                  Therefore the NAND-NAND implementation
                  of the circuit will be as:
                                   A      B      C      D














                                                                                     F










                  (i)  For NOR-NOR Implementation. we take    (i)  NOR Bpåßb_|Q>oeZ hoVw h_ POS ê$n H$m ì`§OH$
                      POS Form:                                   boVo h¢:

                                  F =  (A +  B +  C +  D ) ( . A +  B +  C ) ( . B +  C +  D ) ( . B +  C +  D )
                                    A      B      C      D












                                                                                   F
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