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NPP Number System, Boolean Algebra and Logic Circuits 251
Put one bubble at the output of each OR àË`oH$ OR JoQ> Ho$ AmCQ>nwQ> na EH$ ~~b bJmVo h¢Ÿ&
Gate. One bubbled AND gate is obtained. Con- Bggo EH$ ~~ëS> AND JoQ> ^r àmßV hmoJmŸ& Bgo NOR
vert four NOT Gates into shorted NOR and the
bubbled AND gate into NOR. The resulting JoQ> _| n[ad{V©V H$a gH$Vo h¢Ÿ& gmW hr gmao NOT JoQ>m|
logic circuit contains NOR-NOR Gates only: H$mo em°Q>}S> NOR _| ~XbZo na:
A B C D
F
(e) The given expression is (e) ì`§OH$ F = Σm (0, 1, 2, 4) + d (3, 5, 7) hoVw
F = Σm (0, 1, 2, 4) + d (3, 5, 7) {ZåZ K-_on àmßV hmoJm:
The K-map for the above expression can
be drawn as:
A B C 00 01 11 10
0 1 1 x 1
1 1 x x 0
SOP Form Solution SOP \$m°_© gm°ë`yeZ
Take the same k-map and make group of SOP Ho$ ê$n _| hb H$aZo hoVw k-‘¡n br{OE VWm
‘1’. '1' Ho$ g_yh ~ZmVo h¢…
A B C 00 01 11 10
0 1 1 x 1
1 1 x x 0