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254 Fundamentals of Computers NPP
SOP Form Solution: Take ‘1’ to make SOP \$m°_© gm°ë`yeZ: gmon ê$n _| hb àmßV H$aZo
groups.
hoVw '1' Ho$ J«wn ~ZmZo na
A B C 00 01 11 10
0 x x 1 1
1 0 x 0 1
One quad overlaps with one pair. The sim- EH$ ŠdmS> VWm EH$ no`a Amodabon H$a aho h¢Ÿ& BZ
plified expression in SOP Form is :
XmoZm| go àmßV nXm| H$m Vm{H©$H$ `moJ boZo na …
F = A + C . B
POS Form Solution : Take k-map and use POS \$m°_©: POS ê$n _| hb àmßV H$aZo hoVw '0' Ho$
‘0’ to groups: NPP J«wn ~ZmZo na
A B C 00 01 11 10
0 x x 1 1
1 0 x 0 1
The simplified expression in POS Form can XmoZm| J«wnm| Ho$ nXm| H$m Vm{H©$H$ `moJ boZo na…
be obtained as follows: F = . B (A + C ) F = . B (A + C )
Implementation Using Universal Gates `y{Zdg©c JoQ²>g Ho$ Cn`moJ Ûmam Bpåßc_|Q>oeÝg
(i) NAND-NAND implementation. Take SOP (i) NAND Bpåßb_|Q>oeZ àmßV H$aZo hoVw SOP ê$n _|
form: F = A + C . B Draw logic circuit us- gab ì`§OH$ F = A+ C . B H$m _yb^yV JoQ> `wº$ n[anW
ing basic gates: ~ZmZo na…
A
B F
c
Convert AND into NAND, the circuit can AND H$mo NAND _| ~XbH$a nwZ… n[anW ~ZmZo
be redrawn as: na