Page 139 - Modul Aljabar
P. 139
2 −1 1 1
̅
̅
a. ( ) = = [ ] [ ] = [ ]
−8 4 2 2
2 −1 1 0
Kernel = [ ] [ ] = [ ]
−8 4 2 0
2 −1 −1 −2 + 4 2 0
[ ] [ ] = [ ] = [ ] ≠ [ ]
−8 4 −4 8 + (−16) −8 0
−1
[ ] bukan terletak ( )
−4
2 −1 1 5
b. [ ] [ ] = [ ]
−8 4 2 0
1 1
2 −1 1 1 − 1 −
[ ] . ~ [ 2] + 8 ~ [ 2]
−8 4 1 2 −8 4 2 1 0 0
1
1 − 1 5
[ 2] [ ] = [ ]
0 0 2 0
1
1
− = 5 → = 5 +
1
1
2
2 2
1
Misal: = 1, = 5
1
2
2
0. − 0. = 0
1
2
5
Karena dan konsisten maka [ ] merupakan ( )
2
1
0
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