Page 152 - Buku PD 2020 Lengkap Pak Panjaitan

1 1
2
5
3
= ( + + + )
2
1
20 6
C. Masalah Nilai Awal
Selesaikan Masalah nilai awal berikut ini:

′′
′
1. − = , ( ) = , ( ) =
′′
′′′
′
′′
2. + − = , ( ) = , ( ) = , ( ) =
′
′
′′
3. + − = , ( ) = , ( ) = −

′′
′
4. − = , ( ), ( ) = −

′
5. ( + + ) = , ( ) = , ( ) = −

′

6. ( + ) = , ( ) = , ( ) =

′

7. ( + + ) = + + , ( ) = , ( ) = −
′
′′
′
8. + + = − , ( ) = , ( ) = ,
′
′′
′

9. − + = − + , ( ) = , , ( ) = ,
′
′′
10. − = , ( ) = − , ( ) =

Jawaban:
′′
′
1. − = , ( ) = , ( ) =
P.D ini dapat ditulis dalam operator D

2
( − 4) = 0

Persamaan karakteristik

2
− 4 ≠ 0

⇔( + 2)( − 2) ≠ 0

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