Page 321 - Matematika_XI_Siswa

Alternatif Penyelesaian:
3
a) ∫ 2x 4 x dx = ∫ 2.x dx
3
4
x
2
3
= 2 x 4 .x dx
∫
2
3
∫
= 2 x 4+ 2 dx
 11 
= 2   11 1 x 2 + 1 + c  
 + 1 
 2 

 13 

1
= 2   13 x + c
2

 
 2 
4 13
= x + . c
2
13

b) ∫(x + 1) dx = ∫ x + 2 2x + 1dx
2
1 2
= x 2 1 + x 11 ++
+
+
xc
2 1 11
+
+
1
3
2
xc
= x + x ++ .
3

MATEMATIKA 311